> On 11 Jul 2022, at 1:01 pm, [email protected] <[email protected]>
> wrote:
>
> Holger, my MINUS expression is a UNION of several things, but here is the
> relevant part:
> [
> sh:path [
> sh:inversePath rdf:type ;
> ] ;
> sh:nodes [
> sh:path enterprise_schemas:excludedConceptTypes ;
> ] ;
> ]
>
> (The values of enterprise_schemas:excludedConceptTypes are calculated
> individually for each resource.)
>
> Does this help?
Sorry, no, this doesn’t really clarify it for me. It doesn’t give me enough
detail to have an executable toy example. Have you tried the hasValue solution
or the ASK below? Where exactly are you stuck?
Holger
> On Thursday, July 7, 2022 at 12:43:17 PM UTC-7 Holger Knublauch wrote:
> sh:class will always include subclasses too. But to do direct matching you
> could probably do
>
> [ sh:property [ sh:path rdf:type ; sh:hasValue CLASS ] ]
>
> Or use SPARQL as in
>
> [ sh:ask “ASK { $this a CLASS }” ]
>
> (It’s hard to advise you without seeing the full sh:values rule that you
> have, so above are my best guesses).
>
> Holger
>
>
>
>> On 7 Jul 2022, at 3:08 pm, Carl Burnett <[email protected]
>> <applewebdata://A682EE58-F4AA-4C98-B4C0-44B6C791587A>> wrote:
>>
>
>> I’ve written some sh:values rules for a property shape that filter out
>> (using a sh:minus expression) results that have certain rdf:types. My rules
>> work as desired except when a result has a type that is a subclass of a
>> “banned” class and it is filtered out, which I don’t want.
>>
>> Is there a way to specify that I only want my rule to filter out values that
>> have the actual types I specify – not their subclasses?
>>
>> Carl Burnett (he/him)
>> Senior Ontology Engineer | Healthwise
>> [email protected] <applewebdata://A682EE58-F4AA-4C98-B4C0-44B6C791587A>
>> | www.healthwise.org <http://www.healthwise.org/>
>> 208.489.8485 <tel:(208)%20489-8485>
>>
>>
>
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