Thx for that one,
I've try your latest hint too, but i didn't know that you can check 
zero references like you did!

> criteria.add(AdressenreferenzPeer.KUNDENADRESS_ID, ??0??,
>       Criteria.ISNULL);

In your criteria what is the second param  in the signature doing?
What is the 0 indicating?

Oh btw, your code is working fine!
Thx again...

Jan
 

-----Ursprüngliche Nachricht-----
Von: Thomas Vandahl [mailto:[EMAIL PROTECTED] 
Gesendet: Freitag, 20. Oktober 2006 12:24
An: Apache Torque Users List
Betreff: Re: AW: Problems to set up a subquery

Pfiester, Jan wrote:
> Hello Thomas,
> I totally agree with you, but still i'm not able to come up with a solution i 
> would call a good one.
> Can you please tell me what i'm doing wrong in the code below:
> 
> My current working solution but not considered as a good one:
>       Criteria criteria = new Criteria();
>       criteria.add(   
>               KundenadressePeer.KUNDENADRESS_ID, 
>               (Object)"kundenadresse.KUNDENADRESS_ID NOT IN (SELECT 
> adressenreferenz.KUNDENADRESS_ID                                  FROM 
> adressenreferenz)", 
>               Criteria.CUSTOM
>       );
>               
> Sort of a "clean" approach, but not working due sql exections:
>       Criteria subCriteria = new Criteria();
>       subCriteria.add(AdressenreferenzPeer.KUNDENADRESS_ID, Criteria.ALL);
>               
>       Criteria criteria = new Criteria();
>       criteria.add(KundenadressePeer.KUNDEN_ID, kundeId, Criteria.EQUAL);
>       criteria.addNotIn(KundenadressePeer.KUNDENADRESS_ID, 
> AdressenreferenzPeer.doSelect(subCriteria));
> 
>       return KundenadressePeer.doSelect(criteria);
> 

My suggestion uses a join instead of a subquery:

    Criteria criteria = new Criteria();
    criteria.addJoin(KundenadressePeer.KUNDENADRESS_ID,
        AdressenreferenzPeer.KUNDENADRESS_ID,
        Criteria.LEFT_JOIN);

    criteria.add(AdressenreferenzPeer.KUNDENADRESS_ID, 0,
        Criteria.ISNULL);

    return KundenadressePeer.doSelect(criteria);


Bye, Thomas.

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