Hi,
I've written a macro that takes RDF and converts it to HTML and
inserts it in a wiki page.
The macro will take an attachment on the current page and render it,
it works like this:
[[RdfView(example.rdf)]]
In my macro code, I've figured out how to get the filename, but I need
the actual path to it (not URL) so I can open it and run it through an
RDF parser.
def expand_macro(self, formatter, name, content):
#'content' is the attachment filename
So I need to do something like os.path.join(SOME_FUNCTION(), content))
What function will give me that path?
Thanks,
Rob
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