The following errata report has been submitted for RFC9162,
"Certificate Transparency Version 2.0".

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You may review the report below and at:
https://www.rfc-editor.org/errata/eid8670

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Type: Editorial
Reported by: Niels Möller <[email protected]>

Section: 2.1.3.2

Original Text
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           ii.  If LSB(fn) is not set, then right-shift both fn and sn
                equally until either LSB(fn) is set or fn is 0.

Corrected Text
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           ii.  If LSB(fn) is not set, then right-shift both fn and sn
                equally until LSB(fn) is set.


Notes
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This even case can happen only when fn == sn > 0, which means that the shifting 
loop always terminates with fn odd (and hence non-zero).

Suggesting that fn == 0 can happen is confusing, since in this case the 
preceding update of r, using a path element as *left* sibling, makes no sense. 
Not sure if it would be helpful to also add a comment explaining why the loop 
terminates.

The same correction applies to 2.1.4.2, algorithm step 6.b.iii.

Instructions:
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RFC9162 (draft-ietf-trans-rfc6962-bis-42)
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Title               : Certificate Transparency Version 2.0
Publication Date    : December 2021
Author(s)           : B. Laurie, E. Messeri, R. Stradling
Category            : EXPERIMENTAL
Source              : Public Notary Transparency
Stream              : IETF
Verifying Party     : IESG

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