On 15/07/13 12:07 +0200, Nicolas Évrard wrote: > * Cédric Krier [2013-07-15 00:20 +0200]: > >Hi, > > > >I would like to submit this poll for this change: > > > >http://codereview.tryton.org/969002/#msg9 > > > > kg.convert(1000, gr) == 1 > > > > gr.convert(1000, kg) == 1 > > > > > >Which one is more logical/easy/right? > > For me they are almost the same. > > Would it be possible to make something like: > > (g / kg) * 1000 == 1
Looks great but it is missing the rounding so code will be:
kg.round((g / kg) * 2000) == 2
which makes it lost his consistancy.
--
Cédric Krier
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