On 08 May 09:11, Sergi Almacellas Abellana wrote:
> El 08/05/15 a les 09:07, Raimon Esteve ha escrit:
> >Hie,
> >
> >I like to call a wizard GUI (popup) from a custom method. My scenario:
> >
> >1- A button, call a method example().
> >2. The method example(), depend state, call other method. For example:
> > - Draft state call example_draft()
> > - Done state call example_done()
> >
> >About example method:
> >
> >def example():
> > if state == 'done':
> > example_done()
> > else:
> > example_draft()
> >
> >Now, in case is done(), I like to open a GUI wizard. For example:
> >
> >def example_done():
> > # Here I check some parts
> > ...
> > if someting:
> > # Call a wizard GUI. How do it?
> > else:
> > # Not do nothing
> > return
> >
> >Of course calling Wizard.create() and Wizard.execute() don't open
> >wizard GUI. I like to do similar @ModelView.button_action but inside a
> >method.
> >
> >Is it possible to do it?
>
> AFAIU what you wan't is a StateAction that call your wizard. Once you have
> this, on your transition simply return the state name of the StateAction
> that points to the wizard and the client will open it.
>
> Example:
>
> class Wizard(Wizard):
>
> start = StateTransition()
> open_wizard = StateAction('xml_id_of_your_wizard')
>
> def transition_start(self):
> return 'open_wizard'
>
Or you can just return the action_id when you want to run it. That's
what does ModelView.button_action decorator.
--
Cédric Krier - B2CK SPRL
Email/Jabber: [email protected]
Tel: +32 472 54 46 59
Website: http://www.b2ck.com/
