Brett McLaughlin wrote:
>
> Scott Tavares wrote:
> >
> > Does anyone know of an ease and efficient way to do this? right know the
> > code i have looks:
> >
> > int index = tableNameSet.indexOf(tableName);
> > if(index != -1){
> > tableNameSet.addElement(tableName);
> > }
Besides, you should really do:
<code>
if (!tableNameSet.contains(tableName))
tableNameSet.addElement(tableName);
</code>
Better, better ;-)
-Brett
> >
> > but what is happening (i think) is the indexOf() method to comparing copies
> > of references of the string instead of comparing the literal values stored
> > in them (the way java does comparisons is so freaking confusing).
>
> what class is this in? i need to know more - what is the type of
> tableNameSet variable? If it is a vector, like it looks:
>
> performing indexOf() on a Vector uses the Objet's equals() method, which
> results in a comparison that is fairly shallow. However, because of the
> literal String pool in Java, (string1 == string2) is exactly the same as
> string1.equals(string2). Keep in mind that in both cases, the case _is_
> sensitive. So if you added tableName earlier as a String, this should
> work fine.
>
> BTW, you might want to bookmark the APIs, they can clear up this type of
> confusion:
>
> http://java.sun.com/products/jdk/1.3/docs/api/index.html
>
> that's JDK 1.3, but you get the idea ;-)
>
> -Brett
> >
> > anyone?....... anyone?......
> >
> > -scott-
> >
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