When I'm trying to use a FileField I got this error:
File "d:\projects\3rd-party\turbogears\turbogears\controllers.py", line 110,
in validate
kw.update(form.validate(value))
File "d:\projects\3rd-party\turbogears\turbogears\widgets\forms.py", line
865, in validate
return self.validator.to_python(value, state)
File
"c:\python24\lib\site-packages\formencode-0.4-py2.4.egg\formencode\api.py",
line 308, in to_python
value = tp(value, state)
File
"c:\python24\lib\site-packages\formencode-0.4-py2.4.egg\formencode\schema.py",
line 132, in _to_python
new[name] = validator.to_python(value, state)
File
"c:\python24\lib\site-packages\formencode-0.4-py2.4.egg\formencode\api.py",
line 297, in to_python
if not value and value != 0:
File "C:\Python24\lib\cgi.py", line 625, in __len__
return len(self.keys())
File "C:\Python24\lib\cgi.py", line 601, in keys
raise TypeError, "not indexable"
TypeError: not indexable
Looks like a formencode/cgi bug to me but nevertheless, it renders stock
FileField unusable.
Using formencode's FieldStorageUploadConverter validator doesn't help either as
the bug happens before it is run.
To workaround the bug I come up with this validator class instead:
class FileUploadConverter(validators.FancyValidator):
def to_python(self, value, state=None):
if isinstance(value, cgi.FieldStorage):
if value.filename:
return value
raise validators.Invalid('invalid', value, state)
else:
return value
I'm not 100% whether this should be reported to formencode' bug tracker or it
has something with TG/CherryPy so decided to post here first.
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