How can I obtain the requested URL? I'm breaking it down for use in navigation. Like so:
URL: http://mysite/home/efile/upload/ Navigation: home > efile > upload Each part is a hyperlink to the controller index for that section. I'm sure there is a solution with CherryPy, though I'm trying not to use CherryPy specific code. Randall --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "TurboGears" group. To post to this group, send email to [email protected] To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/turbogears -~----------~----~----~----~------~----~------~--~---
