On 5/16/07, The Alchemist <[EMAIL PROTECTED]> wrote:
>
> I need to get the source that linked the user to my website. I need
> to by-pass the server (e.g. Apache) so that I get the original
> source. Is there any way I can do this using CherryPy? (e.g.
> cherrypy.response.headers etc?)
>
You don't need to bypass Apache:
cherrypy.request.headers.get('Referer', None)
This will get the referer's url or, if someone accessed your site
directly, will return None.
Lee
--
Lee McFadden
blog: http://www.splee.co.uk
work: http://fireflisystems.com
skype: fireflisystems
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