Hi Alberto,
I've looked at various threads and I think I am close, except for a
little detail that escapes me.
Here's what I have:
I create a Widget class derivative:
class MakeImgTag(Widget):
params = ['picture_url']
template='''<img src="${picture_url}"/>'''
inside my Root method, I declare the PaginateDataGrid fields as
follows:
pacts_field = [
('ID', 'id'),
(PaginateDataGrid.Column(name='Picture',
getter=MakeImgTag(picture_url='picture_url'))),
...
based on this object inside model.py:
class Pact(SQLObject):
picture_url = StringCol(length=150, varchar=True,title="Main
Picture URL")
...
and on the rendered page I got the following:
<img src="picture_url">
So it's obvious that I don't know how to pass the *value* of the
object field named 'picture_url' into the PaginateDataGrid.Column()
Any pointers?
Will
On Aug 28, 3:34 pm, Alberto Valverde <[EMAIL PROTECTED]> wrote:
> On Aug 28, 2007, at 9:50 PM, shadowfox wrote:
>
>
>
> > Hi all,
>
> > Can anyone direct me to show a picture in a DataGrid widget, or
> > recommend another widget to accomplish this.
>
> > Hopefully I'm not the only one who needs this feature.
>
> Check out this thread:http://tinyurl.com/2l34vh
>
> Alberto
--~--~---------~--~----~------------~-------~--~----~
You received this message because you are subscribed to the Google Groups
"TurboGears" group.
To post to this group, send email to [email protected]
To unsubscribe from this group, send email to [EMAIL PROTECTED]
For more options, visit this group at
http://groups.google.com/group/turbogears?hl=en
-~----------~----~----~----~------~----~------~--~---
