If you create your HelperContext using SDOUtil.createHelperContext(true), XSDHelper.define() will then let you add new types to an existing namespace and also to replace an existing type with a new version (Note: this is a "use at your own risk" feature).
So, you could add a new property by calling XSDHelper.define() again passing in a new version of the XSD type that includes the new element/attribute. Maybe we should consider makingTypeHelper.define() also allow you to modify existing types if the HelperContext has extensibleNamespaces == true? Frank. Ron Gavlin <[EMAIL PROTECTED]> 07/25/2007 03:55 PM Please respond to [email protected] To tuscany-user tuscany-user <[email protected]> cc Subject How to add Property to an XSDHelper-defined Type Greetings, I have a Type that was created using XSDHelper.define(). Now I would like to dynamically add an add'l Property to this Type. This does not appear to be supported. Can you suggest any workarounds? - Ron --------------------------------------------------------------------- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] --------------------------------------------------------------------- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
