[Brian van den Broek] ...
Or, so I thought. I'd first tried getting the alarm datetime by simply taking the date component of datetime.datetime.now() and adding to the day value. That works fine, provided you are not on the last day of the month. But, when checking boundary cases before posting the code I sent, I discovered this sort of thing:
last_day_of_june = datetime.datetime(2004, 6, 30) # long for clarity ldj = last_day_of_june # short for typing new_day = datetime.datetime(ldj.year, ldj.month, ldj.day + 1)
Traceback (most recent call last): File "<pyshell#8>", line 1, in -toplevel- new_day = datetime.datetime(ldj.year, ldj.month, ldj.day + 1) ValueError: day is out of range for month
So, adding to the day or the month was out, unless I wanted elaborate code to determine which to add to under what circumstances.
Actually, you needed simpler code <wink>:
import datetime ldj = datetime.datetime(2004, 6, 30) new_day = ldj + datetime.timedelta(days=1) print new_day
2004-07-01 00:00:00
or even
ldy = datetime.datetime(2004, 12, 31) new_day = ldy + datetime.timedelta(days=1) print new_day
2005-01-01 00:00:00
In other words, if you want to move to the next day, add one day! That always does the right thing. Subtracting one day moves to the
previous day, and so on.
Hi Tim and all,
thanks! Since I last posted, I'd found a better way to do what I wanted
than what I'd been using. But it was still clumsy. Your way is of much better than any work-aroundish thing.
It does, however, prove my claim up-thread that I'd only skimmed the datetime docs!
Best to all,
Brian
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