> >>> a
> ['a', 'apple', 'b', 'boy', 'c', 'cat']
>
> I want to create a dictionary:
> dict = {'a':'apple',
> 'b':'boy',
> 'c':'cat'}
>
>
> Problem:
> How do i capture every alternative element in list a:
>From first principles:
n = 0
while n < len(a):
keys.append(a[n])
vals.append(a[n+1])
n += 2
Or using Python a little more:
tups = []
for n in range(0,len(a),2): # step 2
tups.append( (a[n],a[n+1]) ) #list of tuples
d = dict(tups)
Or using it a bit more:
d = dict([(a[n],a[n+1]) for n in range(0,len(a),2)])
For readability's sake I'd use the middle version.
HTH
Alan G.
>
> I am unable to pump the a,b, and c into keys list
> and apple, boy,cat into vals list.
>
> Trial 1:
> >>> while i >= len(a):
> print a[i]
> i = i+2 -- I thought i+2 will give me alternative
> elements
>
> Trial 2:
> >>> for index,i in enumerate(range(len(a))):
> print a[i]
> print a[index+1]
>
>
> a
> apple
> apple
> b
> b
> boy
> boy
> c
> c
> cat
> cat
>
> Please help me. It is also time for me to refer my
> prev. notes :-(
>
> thanks
> K
>
>
>
>
>
>
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