Hi group: I have two lists a. 'my_report' and b. 'what'. In list 'what', I want to take 6649 (element1: 164:623\t6649) and write to a new list ( although I printed the result, my intension is to list.append(result).
I took column 1 value of element 1 in what, which is 164:623 and checked in column 1 value in list my_report, if it matches I asked it to write the all columns of my_report along with column 2 value in what list. (with my explanation, I feel I made it complex). Here is what I did: >>> what[0:4] ['164:623\t6649', '484:11\t6687', '490:339\t6759', '247:57\t6880', '113:623\t6901'] >>>my_report[0:4] ['164:623\tTCATGGCTGACAACCCATCTTGGGA\t200000_s_at', '484:11\tATTATCATCACATGCAGCTTCACGC\t200000_s_at', '490:339\tGAATGGGGCCGCCAGAACACAGACA\t200000_s_at', '247:57\tAGTCCTCGTGGAACTACAACTTCAT\t200000_s_at', '113:623\tTCATGGGTGTTCGGCATGACCCCAA\t200000_s_at'] >>>for i in range(len(what)): ele = split(what[i],'\t') cor1 = ele[0] for k in range(len(my_report)): cols = split(my_report[k],'\t') cor = cols[0] if cor1 == cor: print cor+'\t'+ele[1]+'\t'+cols[1]+'\t'+cols[2] 164:623 6649 TCATGGCTGACAACCCATCTTGGGA 484:11 6687 ATTATCATCACATGCAGCTTCACGC 490:339 6759 GAATGGGGCCGCCAGAACACAGACA 247:57 6880 AGTCCTCGTGGAACTACAACTTCAT 113:623 6901 TCATGGGTGTTCGGCATGACCCCAA PROBLEM: This process is very very slow. I have 249502 elements in each list. The process has been running for over 30 min. Could any one suggest a better fast procedure, to save time. Thank you in advance. K __________________________________ Do you Yahoo!? Yahoo! Mail - Easier than ever with enhanced search. Learn more. http://info.mail.yahoo.com/mail_250 _______________________________________________ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor