Hi kumar
If I unterstood your question correctly, you have to iterate over the refseq
until
you get the next entry, which starts with a '>'
on Tue, 18 Jan 2005 20:12:32 -0800 (PST) kumar s <[EMAIL PROTECTED]> wrote :
---------------------------------------------------------------------------------------------
kumar s > I could not think of any smart way to do this,
kumar s > although I have tried like this:
kumar s >
kumar s > >>> for ele1 in Lseq:
kumar s > for ele2 in refseq:
kumar s > if ele1 in ele2:
kumar s > k = ele2
kumar s > s = refseq[ele2].startswith('>')
Here you index the list with an element, but the index must be an integer
kumar s > print k,s
kumar s >
kumar s >
kumar s >
kumar s > Traceback (most recent call last):
kumar s > File "<pyshell#261>", line 5, in -toplevel-
kumar s > s = refseq[ele2].startswith('>')
kumar s > TypeError: list indices must be integers
kumar s >
kumar s >
kumar s > I do not know how to dictate to python to select lines
kumar s > between two > symbols.
kumar s >
------------------- end ----------------------
Perhaps this is a possible solution:
Iteration of Lseq an then looping over all elements in refseq.
if an element of refseq contains the ele1 the list-entry is printed.
The nested while-loop print's the refseq -elements as long as the element
does not start with a '>'
for ele1 in Lseq:
i=0
while i < len(refseq):
if ele1 in refseq[i]:
print refseq[i]
i +=1
while not refseq[i].startswith('>'):
print refseq[i]
i+=1 # increment until the next entry starting
with '>' is found
i +=1 # if search should continue if another element is present
HTH Ewald
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