Jacob S. wrote:
Actually, this doesn't even work 100% of the time. If you have a list as the key or value in a dictionary, it will remove the brackets, at which point eval will fail since the dictionary will look likeAhh, my pitiful form of flattening a list that cheats...
def flatten(li): li = str(li) li = li.replace("[","") li = li.replace("]","") li = li.replace("(","") li = li.replace(")","") li = "[%s]"%li return eval(li)
It works! It's probably just a bit slower.
Jacob Schmidt
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{7:8,9,10} (assuming an original dictionary of {7:[8,9,10]}), which results in a SyntaxError
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