I got this from spyce http://spyce.sourceforge.net
_url_ch = re.compile(r'[^A-Za-z0-9_.!~*()-]') # RFC 2396 section 2.3 def url_encode(o, **kwargs): '''Return URL-encoded string.''' return _url_ch.sub(lambda match: "%%%02X" % ord(match.group(0)), str(o)) It was just the first thing I found in google "python url encode" Good Luck Luis N wrote: >How would I best turn this string: > > > >'2005-01-24 00:00:00.0' > > > >into this string: > > > >'2005%2D01%2D24%2000%3A00%3A00%2E0' > > > >In order to call a URL. > > > >I've hunted through the standard library, but nothing seemed to jump out. > > > >Thank You. > >_______________________________________________ > >Tutor maillist - [email protected] > >http://mail.python.org/mailman/listinfo/tutor > > > > > __________________________________ Do you Yahoo!? Meet the all-new My Yahoo! - Try it today! http://my.yahoo.com _______________________________________________ Tutor maillist - [email protected] http://mail.python.org/mailman/listinfo/tutor
