SEveral solutions here.
The best is to restructure the code a little:
> def go_jogging():
> # go out and jog
> return
>
> if not bad_weather == 'y': # where is this initially set BTW?
go_jogging()
else
> # ask user only if weather is bad.
> b = input ( "Weather is really bad, still go out to jog?[y/n]" )
> if b == 'y':
> go_jogging()
Its shorter, simpler and makes the most common case the default
(assuming that bad weather is the exception!)
> I can't get the program to stop processing further in the middle
Good, that would be really bad practice from a structured programming
point of view. :-)
But if you really, really must, you could always call
raise SystemExit
which bombs out more or less immediately - like exit() in C....
> C++ mindset) so I used exception to achieve what I want.
Yes thats ok, and the exception to use is already there...
> example you could probably manipulate the logic so that program ends
at
> the bottom of the if-tree. My question is then how to exit in the
middle
> of a if-then-else tree?
You should never need to. One of the things that structured
programming
(Edsgar Dijkstra to be precise) showed was that you can *always*
rearrange
things so that goto's and intermediate exits are not needed and indeed
can introduce an extra level of complexity and error.
Alan G
Author of the Learn to Program web tutor
http://www.freenetpages.co.uk/hp/alan.gauld
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