You could make the __init__ take the filename: def __init__(self, filename=None): #do whatever
And then instantiate the object like: >>>x = someClass(filename="someFile") Alternatively, you could make the Open function a module level function, defined in someClass.py, but not in the actual class definition. There's also a way to do it with @staticmethod, but I haven't ever touched that. Thanks, Ryan -----Original Message----- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On Behalf Of Christian Meesters Sent: Monday, February 21, 2005 5:01 AM To: tutor@python.org Subject: [Tutor] Initializing with a call like: someClass.open("someFile")? Hi My cryptic subject is perhaps not sufficient - I'll try to make it a little better: Assume you'd like to write something like: import someClass x = someClass.open("someFile") Here '.open' should read in the data and initialize the instance - with or without calling __init__. How is this to implement? Up to now I rather wrote something like x = someClass(somePrepFunction("someFile")) where the return value of somePrepFunction was used to initialize x or called the conventional 'open' within __init__. But is there no direct approach like in my pseudo-code? My problem is that if I simply define open as a method of someClass (with def open(self,file_name): #somecode pass ) all I get is: TypeError: unbound method open() must be called with someClass instance as first argument (got str instance instead) Which is perfectly understandable. But what is a possible workaround? (Instead of 'open' I could, of course, better use some other keyword which is no Python keyword.) Any hints? Thanks a lot in advance. Christian _______________________________________________ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor _______________________________________________ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
