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---------- Forwarded message ----------
Date: Wed, 16 Mar 2005 23:03:13 +1100
From: oscar ng <[EMAIL PROTECTED]>
To: 'Danny Yoo' <[EMAIL PROTECTED]>
Subject: RE: [Tutor] Newbie in Python (fwd)
Hi Danny,
Thanks for the reference. I managed to read all the folders and am able
to open all the files in the directory using a for loop
Here is the code:
def getFiles(parent):
#used to get the parent directory for the files to process
mainFolder = os.listdir(parent)
for a in mainFolder:
if os.path.isdir(parent + "/" + a):
subfolders = [a] ##set the subfolders to the its
##categories
print subfolders
getFiles(parent + "/" + a)
else:
fileName = [parent + "/" + a]
listFile = a #listFile is a list that holds the name
of #files
#print listFile,
#listFile[a] +=1
#print listFile
words=[]
for b in fileName:
inputFile = open(b) #inputFile holds the
#individual/basic files to be
#processed
listText = inputFile.read() #listText holds entire texts
of #all the files
from parent
#directory
print listText
I need now to ask how I can process the headers "subject" of each
individual email/file as the content of the "subject" determines the
appropriate category I need to place them into. As listtext only prints
all the emails in the folder.
Also is there a way I can count the number of files ie listFile[a] +=1
as this keeps giving errors when running it.
Thanks heaps
Oscar
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