hi Max, you can use: alph = ["a","b", ....] myString = "".join(alph) print myString
regards, tanja On 5/7/05, Max Russell <[EMAIL PROTECTED]> wrote: > Hello- > > I've started writing a suite of tools to help me do > Crypto puzzles (slowly...) My first snippet of code > allos me to print out a Caesar shifting alphabet, as I > tend to write them out by hand; which is a waste of > time. > > alph = > ["a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u","v","w","x","y","z"] > print "\n" > print alph > print "\n" > x = 1 > while x < 26: > alph.append(alph.pop(0)) > print alph > print "\n" > x += 1 > > anyway- I don't like the output which come in the > form: > ['b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', > 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', > 'w', 'x', 'y', 'z', 'a'] > > What I'd like to do is take my list and turn it into a > string, which looks neater when printed. > > I've tried using join() but that didn't work, can > anyone give me a pointer here? > > the other method I've used was dealing with a string > directly: > alph = 'abcdefghijklmnopqrstuvwxyz' > print alph > #print "\n" > > x = 1 > > while x < 26: > new_alph = alph[1:] + alph[:1] > print new_alph > print "\n" > x += 1 > > But this has the drawback of not progressing with my > newly create alphabet, it just returns: > abcdefghijklmnopqrstuvwxyz > bcdefghijklmnopqrstuvwxyza > > bcdefghijklmnopqrstuvwxyza > > etc... > > HELP!! > > thanks > Max > > > ___________________________________________________________ > Yahoo! Messenger - want a free and easy way to contact your friends online? > http://uk.messenger.yahoo.com > _______________________________________________ > Tutor maillist - [email protected] > http://mail.python.org/mailman/listinfo/tutor > -- www.klaustrofobik.org _______________________________________________ Tutor maillist - [email protected] http://mail.python.org/mailman/listinfo/tutor
