On Tue, 7 Jun 2005, Terry Carroll wrote: > On Tue, 7 Jun 2005, D. Hartley wrote: > > > def findlist(): > > newlist = [] > > for i in range(480): > > line = fromlist[:640] > > del fromlist[:640] > > x = line.index(195) > > y = x + 5 > > z = line[x:y] > > del line[x:y] > > for i in z: > > newlist.append(i) > > for i in line: > > newlist.append(i) > > return newlist > > where does the variable named "fromlist" come from? It's not passed into > the method as a parameter.
I'm thinking more and more that this is the issue. Take a look at this, and see if it gives you the flavor. Only the third approach actually gives you what (I think) you want, rather than reusing the same list over and over. def testit1(): print fromlist1[0] del fromlist1[0] return fromlist1 = ['a', 'b', 'c', 'd'] print "testit1: Denise problem" testit1() testit1() testit1() def testit2(flist): print flist[0] del flist[0] return fromlist2 = ['a', 'b', 'c', 'd'] print "testit2: Python Gotcha #6" # http://www.ferg.org/projects/python_gotchas.html testit2(fromlist2) testit2(fromlist2) testit2(fromlist2) def testit3(flist): mylist = flist[:] # copy the list rather than mutating it for next time print mylist[0] del mylist[0] return fromlist3 = ['a', 'b', 'c', 'd'] print "testit3: the right way" testit3(fromlist3) testit3(fromlist3) testit3(fromlist3) _______________________________________________ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
