Here is the code then:
I'll throw in some suggestions. 1 - check for balanced parentheses. This has bit you before and you have several lines below with unbalanced parentheses. 2 - since Python indexes start at 0, take advantage of this. Use random.choice(range(13) and use the value to index the cards list.
#This is code for a blackjack game.
import random
cash = 0
new_cash = 100
cards = {"Ace", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine", "Ten", "Jack", "Queen", "King"}
card_types = {"Diamond", "Heart", "Spade", "Club"}
bet = 0
playertotal = 0
comp_total = 0
def menu():
print "1. Bet and play."
print "2. Cash out and Exit"
def option():
return int(raw_input("Menu choice: "))
def card_choice():
return random.choice(range(1,14)
This will return one number. The statement below (a,b = card_choice()) expects a tuple of 2 numbers to be returned.
def types():
return random.choice(range(1,5)
def player_cards():
print a," of ",t1
print b," of ",t2
print "Blackjack"
print "By Nathan Pinno"
while 1:
menu()
choice = option()
if choice == 1:
bet = int(raw_input("How much do you want to bet: ")
Something is wrong with the indentation below. Assuming the if and else following the while are indented more, you have a BIG problem. What will happen if bet > new_cash? Endless loop printing the Sorry... forever
while 1:
if bet > new_cash:
print "Sorry, you don't have that much cash! Your total cash is: $",new_cash
else:
break
a,b = card_choice()
t1,t2 = types()
if t1 == 1:
t1 = card_types[0]
elif t1 == 2:
t1 = cardtypes[1]
elif t1 == 3:
t1 = cardtypes[2]
else:
t1 = cardtypes[3]
Why not just use the random integer as an index? If you use range(13) these if/elifs become
t1 = cardtypes[t1]
if a == 1:
a = cards[0]
playertotal = playertotal + 1
elif a == 2:
a = cards[1]
playertotal = playertotal + 2
Same thing here.
What are the functions of b, t2, and playertotal? Especially for those of us who don't know blackjack.
Does that help?
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