On Sat, 13 Aug 2005, Jonas Melian wrote:
> I would check 3 words at the starting of a line
>
> s=['foo','bar','qwe']
>
> if ln.startswith(s): (this is bad)
Hi Jonas,
Just checking: is this similar to a question brought up a few days ago?
http://mail.python.org/pipermail/tutor/2005-August/040592.html
Do you really need to do this in one line, or would it be sufficient to
write a function definition that you can reuse? You mentioned earlier
that:
> if ln.startswith(s): (this is bad)
But the general idea is a good one! You can write your own function
called startswithany(), which will then read as:
if startswithany(ln, s): ...
and writing a simple version of startswithany() should be straightforward.
> what is the best way for making it?
>
> if max(map(ln.startswith,s)):
> or
> reduce(lambda m,n:m or n, map(ln.startswith, s))
I'm not so sure about this. It does more work than it needs to, and it
doesn't scan well for human beings. *grin*
If you really want to do it this way, at leeast wrap the it in a
well-named function. But if you really insist on getting it done in one
line, take a look at the Regular Expression HOWTO:
http://www.amk.ca/python/howto/regex/
Good luck to you!
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