I've done:
undup = []
for i in list:
if i not in undup:
undup.append(i)
Which is simple an not very pythonic, but does the trick.
Hugo
Jonas Melian wrote:
> I get a list of repeated numbers [24, 24, 24, 16, 16, 15, 15 ]
> Is possible get it without repeated numbers, without using set()?
>
> If I use set, then the list is unsorted and i cann't sorting it.
>
> For get the values i use:
>
> [x[0] for x in cardTmp]
>
> or:
>
> from itertools import imap
> for i in imap(lambda x: x[0], cardTmp): print i
>
> A idea it would be create a generator that will return elements one by
> one, and then it would be possible know if that element is in the new
> list. But generators are in 2.4
>
>
> Python 2.3.5
>
> _______________________________________________
> Tutor maillist - Tutor@python.org
> http://mail.python.org/mailman/listinfo/tutor
>
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