Bernard Lebel wrote: > Ok I think I understand what is going: I'm using a 0 in the > replacement argument, between the two groups. If I try with a letter > or other types of characters it works fine. So how can use a digit > here?
There is a longer syntax for \1 - \g<1> means the same thing but without the ambiguity of where it ends. So you can use r'\g<1>0\2' as your substitution string. >>def matchShot( sSubString ): >> >> # Create regular expression object >> oRe = re.compile( "(\d\d_\d\d\_)(\d\d)" ) >> >> oMatch = oRe.search( sSubString ) >> if oMatch != None: >> sNewString = oRe.sub( r'\10\2', sSubString ) >> return sNewString >> else: >> return sSubString You don't have to do the search, oRe.sub() won't do anything if there is no match. Also if you are doing this a lot you should pull the re.compile() out of the function (so oRe is a module variable), this is an expensive step that only has to be done once. You hinted in your original post that you are trying to find strings where the last _\d\d has only two digits. The re you are using will also match something like 'mt_03_04_044_anim' and your matchShot() will change that to 'mt_03_04_0044_anim'. If that is not what you want you have to put some kind of a guard at the end of the re - something that won't match a digit. If you always have the _ at the end it is easy, just use r"(\d\d_\d\d\_)(\d\d_)". If you can't count on the underscore you will have to be more clever. Kent _______________________________________________ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
