Thanks for the answer.
I have to confess this question is driven only by curiosity, I was not
even hoping to get such a function. I was reading some stuff about the
scopes in JScript and somehow this question arose in my mind.
For the record, the tutorial I am watching said that a name exists
*only* inside a block, wich is a local scope itself. So that statement
defied my experience with JScript so I wanted to put it to the test:
(this is JScript code ran into a 3D application that embeds Python,
JScript and few other activeX-capable langages).
var oSel = selection(0);
if ( oSel.type == 'polymsh' )
{
var oMesh = oSel;
}
logmessage( oMesh.name );
//Output
//INFO : sphere
Then I was curious if it would have been the same in Python (I knew it
was not, but tested it nonetheless):
oSel = Application.selection(0)
if oSel.type == 'polymsh': oMesh = oSel
Application.logmessage( oMesh.name )
#Output
#INFO : sphere
So then the question arised if it was possible in Python to know to
what scope a name belongs. I don't know any use for this, but I just
wanted to know it was possible.
Thanks!
Bernard
On 10/5/05, Kent Johnson <[EMAIL PROTECTED]> wrote:
> Bernard Lebel wrote:
> > Hello,
> >
> > Anyone know if it is possible to find out in what scope lies a name?
> > For instance, let say I'm using a name in a function, but the name is
> > actually in the global scope. I would like to know if this name was
> > found in what scope. Is it possible at all?
>
> Look for the name in locals() and globals()? But why do you care?
>
> >>> a=1
> >>> def scopeOf(name):
> ... x=3
> ... if name in locals():
> ... print name, 'is local'
> ... elif name in globals():
> ... print name, 'is global'
> ... else:
> ... print 'I don\'t know about', name
> ...
> >>> scopeOf('x')
> x is local
> >>> scopeOf('a')
> a is global
> >>> scopeOf('foo')
> I don't know about foo
>
> This assumes that you actually know the name as a string. If you are trying
> to find out something about the variable in the calling scope then it is
> harder. There are hacks to find out the name of the variable in the calling
> scope but why?
>
> Kent
>
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