I wanted to sum two time values:
-02:30
+01:00
--------------
-01:30
I found one solution:
>>> time_local = dt.time(2,30)
>>> time_str = str(time_local).split(':')
Now I'll can get the first value, convert to integer and sum it.
Kent Johnson wrote:
>Jonas Melian wrote:
>
>
>>I would get the local time of a country, using UTC (Universal Time
>>Coordinated) and DST (Daylight SavingTime) of that country.
>>
>>An example, utc time -02:30 and dst +1 :
>>
>>country_utc = datetime.time(2,30)
>>isUTCNegative = True
>>dst = datetime.time(1,0)
>>
>>Now I would the difference of both times.
>>-02:30 + 01:00 -> -01:30
>>
>>Is possible get sum/difference of time values? How?
>>
>>
>
>I'm not exactly sure what you are looking for, but you can subtract
>datetime.datetime instances. If you are trying to find the difference between
>local time and utc this is one way:
>
> >>> import datetime as dt
> >>> dt.datetime.now()
>datetime.datetime(2005, 10, 20, 19, 41, 30, 393000)
> >>> dt.datetime.utcnow()
>datetime.datetime(2005, 10, 20, 23, 41, 52, 195000)
> >>> dt.datetime.utcnow()-dt.datetime.now()
>datetime.timedelta(0, 14400)
>
>though there is a race condition here that might give you an error of a
>millisecond sometimes.
>
>Kent
>
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>Tutor maillist - Tutor@python.org
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>
>
>
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