Ahh makes much more sense, thanks for all the help! I'll go back and rework it, keeping in mind trying to solve each piece separately.
Thanks again all. -----Original Message----- From: Alan Gauld [mailto:[EMAIL PROTECTED] Sent: Wednesday, October 26, 2005 1:53 AM To: Nick Eberle; bob; tutor@python.org Subject: Re: [Tutor] new user question about while loops As Danny says, try breaking the problem into chunks and solving each bit separately. I'll provide a few comments on your code in the meantime but try the "evolving soluition" approach too. #assigning variables to track the amount of times heads or tails comes up heads=0 tails=1 AG> Why not make both zero, after all there have been no flips so far! flip=100 while flip < 100: AG> flip is never less than 100 because you set it to 100! AG> Thus you never enter the loop... flip -= 1 random.randrange(2) if flip < 100: break AG> And if you did after the first time through you make flip equal 99 AG> so that it will always exit the loop(break) here so it would only run once! AG> Try getting a while loop to run 100 times printing out the loop test value. AG> Or better stuill, since you know how many times you want the lopp to AG> run use a for loop instead: AG> for loop in range(100): AG> # loop code here print "\nThe amount of times tails came up was" , tails , "The amount of times heads came up was" , heads AG> But the only values you assign to head/tails are the initial 1 and 0. AG> Try Danny;'s suggestion of flipping the coin twice... HTH, Alan G Author of the learn to program web tutor http://www.freenetpages.co.uk/hp/alan.gauld _______________________________________________ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
