How's this?: >>> s = """All, ... ... I have a problem/question I'd like to pose to you guys on how best to ... accomplish the following. I have a string that will vary in size, what ... I would like to do is split into n size chunks. I am also not sure how ... best to represent the chunks. For example, say I have a len(s) = 200 ... chars. I'd like to get one chunk with 160 of those chars and the ... remaining 40 in a second. Likewise, if I have a len(s) = 350, I'd like ... two chunks of 160 and a 3rd with the remainder. ... ... I don't know what it would best way to accomplish this. I have the idea ... of converting the string to a list of chars loop through it until size ... is met, create a new string with s=s[:160], then start again, and so ... on. Is this the only way to accomplish this? Or is there a more ... elegant/clever way? ... ... Thank you :)""" >>> l = [] >>> start = 0 >>> for i in range(160, len(s)+160, 160): ... l.append(s[start:i]) ... start = i ... >>>l ["All,\n\nI have a problem/question I'd like to pose to you guys on how best to\naccomplish the following. I have a string that will vary in size, what\nI would like", " to do is split into n size chunks. I am also not sure how\nbest to represent the chunks. For example, say I have a len(s) = 200\nchars. I'd like to get one ch", "unk with 160 of those chars and the\nremaining 40 in a second. Likewise, if I have a len(s) = 350, I'd like\ntwo chunks of 160 and a 3rd with the remainder.\n\nI d", "on't know what it would best way to accomplish this. I have the idea\nof converting the string to a list of chars loop through it until size\nis met, create a ne", '', " to do is split into n size chunks. I am also not sure how\nbest to represent the chunks. For example, say I have a len(s) = 200\nchars. I'd like to get one ch", "unk with 160 of those chars and the\nremaining 40 in a second. Likewise, if I have a len(s) = 350, I'd like\ntwo chunks of 160 and a 3rd with the remainder.\n\nI d", "on't know what it would best way to accomplish this. I have the idea\nof converting the string to a list of chars loop through it until size\nis met, create a ne", 'w string with s=s[:160], then start again, and so\non. Is this the only way to accomplish this? Or is there a more\nelegant/clever way?\n\nThank you :)'] _______________________________________________ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
