Basically it's not evaluating it the way you think it is:
Your first example really equates to:
if (1 or 5) in rollList:
etc...
(1 or 5) equals 1 and 1 isn't in the your list.
On 4/26/06, John Connors <[EMAIL PROTECTED]> wrote:
G'day,
I found something today that has me confused. I'm making a list of 6 random
dice rolls and I want to check if any 1's or 5's were rolled. I tried this
way first and it returns true even if there are no 1's or 5's. I'll use a
roll of all 2's as an example.
rollList = [2,2,2,2,2,2]
if 1 or 5 in rollList:
print 'yes'
else:
print 'no'
Then I tried this and it works fine.
rollList = [2,2,2,2,2,2]
if 1 in rollList or 5 in rollList:
print 'yes'
else:
print 'no'
It doesn't really matter because the second way does what I want but I would
like to know why the first way doesn't work and if the syntax is wrong why
doesn't it return an error.
John
PS I apologise if this is a duplicate, hotmail did some kind of spam check
when I tried to send it, I've waited 30 mins and I don't think it went the
1st time so I'll post it again.
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