junkList =["interchange", "ifferen", "thru"]
The comparison lists have one or more elements, which may or may not contain the junkList elements somewhere within:
l = ["My skull hurts", "Drive the thruway", "Interchangability is not my forte"]
... output would be
["My skull hurts"]
I have used list comprehension to match complete elements, how can I do a partial match?
def removeJunk(reply, junkList):
return [x for x in reply if x not in junkList]
It would be so much prettier than searching through each list element for each term - I tend to get lost in a maze of twisty corridors, all alike.
Thanks!
_______________________________________________ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
