On Thursday 16 November 2006 22:35, John Fouhy wrote: > On 17/11/06, Dave S <[EMAIL PROTECTED]> wrote: > > Hi, > > > > I have a bunch of lists within lists that I need to sort ref item [4], I > > can't access my code at the moment but I basically ... > > [...] > > > Having googled I think there is a better way of doing this with the key > > attribute > > > > a.sort(key= ?? ) > > Yep, that's right. You need at least python2.4 for this, though. > > You need to pass the key= parameter a function that will take an > element of your list, and return the comparison key. > > eg: > > def item4(elem): > return elem[4] > > a.sort(key=item4) > > Since this is a common thing to do, there is a function in the > operator module that you can use, instead of defining your own: > > import operator > a.sort(key=operator.itemgetter(4)) > > (operator.itemgetter(4) will return a function that is basically > equivalent to item4() above) > > HTH!
Sure does - cheers Dave _______________________________________________ Tutor maillist - [email protected] http://mail.python.org/mailman/listinfo/tutor
