Moedeloos Overste wrote:
> Hi everybody,
>
> I'm in the process of learning Python and working my way through O'Reilly's
> "Learning Python". As an excercise I wrote (some copy/paste as well) a small
> lottery program just to learn how to work with lists and dictionarys etc.
>
> The user has to enter 6 numbers from a range(1-45). The numbers are stored
> in a list(num_list). Then the program asks the user how many times(vDraws)
> he wants to play the lottery with his numbers. After entering the program
> draws the lottery the desired number of times and compares the winning
> numbers with the users numbers.
>
> Now, by accident I stumbled upon the following; if the user enters the
> numbers 1 to 6 as his lottery numbers he always wins! So somewhere I must
> have made a mistake. Could somebody have a look at the code please and tell
> me where I took a wrong turn?
>
>
>
> winnings=0
> right2=1
> right3=4
> right4=15
> right5=450
> right6=1000000
>
it might be clearer to do
prizes = [0,0,1,4,15,450,1000000]
> user_nums=[] # empty List for numbers
> print "Kies je nummers tussen 0 en 46"
> print
> whereat=1
> listindex=0
>
What is the point of having two variables here?
You never use listindex.
You should start whereat at 0.
> # when 7th number is inputted loop breaks
> while whereat <= 6:
>
And loop until whereat is less than 6.
That's the general consensus on looping in Computer Science. Starting at 0.
> num=raw_input("Voer "+str(whereat)+". Lotto nummer in: ")
>
And just change this line to str(whereat+1) instead.
> # check that user inputted value is not smaller than 1 or bigger than 45
> # and that it is not already in user_nums
> if num != "" and len(num) != 0:
>
If they enter 'a' your program will crash.
A better solution would be to use a try.... except block.
eg.
try:
tmp = int(num)
if tmp >= 1 and tmp <= 45 and tmp not in user_nums:
user_nums.append(tmp)
whereat += 1
except ValueError:
pass
> if int(num) >= 1 and int(num) <= 45 and num not in user_nums:
> user_nums.append(num)
>
Also note here that you're using the integer representation of num to
compare it to 1 and 45,
but then you're storing the string representation of it in user_nums.
This may be part of why you're having a problem.
> whereat+=1
> listindex+=1
> # if above statement if false just pass and ask for the number
> again!
> else:
> pass
> print '1 trekking kost U 1 euro inzet'
> print
> vDraws = input("Hoe vaak wil je in de lotto spelen met deze nummers? :>")
>
> # Create dictionary for statiscal purposes later on :-)
> d={1:0, 2:0, 3:0, 4:0, 5:0, 6:0, 7:0, 8:0, 9:0, 10:0, 11:0, 12:0, 13:0,
> 14:0, 15:0,
> 16:0, 17:0, 18:0, 19:0, 20:0, 21:0, 22:0, 23:0, 24:0, 25:0, 26:0, 27:0,
> 28:0,
> 29:0, 30:0, 31:0, 32:0, 33:0, 34:0, 35:0, 36:0, 37:0, 38:0, 39:0, 40:0,
> 41:0, 42:0,
> 43:0, 44:0, 45:0}
>
This could be:
d = {}
for x in range(1,46):
d[x] = 0
Or several varations of this, using lambda & map, and such.
> match=0
> count=0
>
You don't use count in your program anywhere.
> inzet=vDraws * 1
>
There's absolutely no reason to multiply something by 1.
> while vDraws > 0:
> x=random.sample(range(1,46), 6)# draws lottery from given range
> for i in x:
> y=int(i)
>
This line is unnecessary, 'i' is already an integer.
> d[y] = int(d[y])+ 1 #stores values in lottonumbers dictionary
>
Can be shortened to d[y] += 1
> for p in user_nums:
> count+=1
>
no reason to do this because the for loop will end when it runs out of
variables.
> y=str(y)
>
Again, if you leave the original items as integers you don't have to do
all this conversion.
> if p in y:
>
I would change this to 'if p == y', because I'm not sure what 'in' is
doing here.
> match+=1 # increase matching variable by one if its right
> number
>
> # caculating winnings
> if match ==2:
> winnings+=right2
> match=0
> elif match ==3:
> winnings+=right3
> match=0
> elif match == 4:
> winnings+=right4
> match=0
> elif match == 5:
> winnings+=right5
> match=0
> elif match == 6:
> winnings+=right6
> match=0
>
Using that prizes list, this can be shortened to
winnings += prizes[match]
match = 0
> vDraws = vDraws - 1
>
Or vDraws -= 1
> # sorting dictionary by its values
> items=d.items()
> backitems=[ [v[1],v[0]] for v in items]
> backitems.sort()
> sortedlist=[ backitems[i][1] for i in range(0,len(backitems))]
>
> print
> print
> print
> saldo=winnings-inzet
> print
> print
> print '-' * 80
> if saldo > 0:
> print 'U heeft', saldo, 'euro winst gemaakt!'
> else:
> print 'U heeft', saldo, ' euro verlies geleden!'
>
>
> print 'U heeft in totaal gewonnen', winnings, 'euro.'
> print 'Uw inzet was', inzet, 'euro'
> print 'De 6 meest gevallen getallen waren:',
> for x in sortedlist[0:6]: print x, #prints the 6 most drawn numbers
>
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