Carlos wrote:
> Hello,
>
> Can you help me with this please?
>
> I have a list that contains elements to be created (in a 3D app), in the
> list each element is a dictionary that contains data, like:
>
> Elements = [
> {'Width': 3.0, 'Depth': 3.0, 'Name': 'Access', 'Parent':
> 'Plot', 'Height': 3.0},
> {'Width': 3.0, 'Depth': 3.0, 'Name': 'Circulation_01',
> 'Parent': 'Access', 'Height': 3.0},
> {'Width': 3.0, 'Depth': 3.0, 'Name': 'Circulation_02',
> 'Parent': 'Access', 'Height': 3.0},
> {'Width': 3.0, 'Depth': 3.0, 'Name': 'Circulation_03',
> 'Parent': 'Access', 'Height': 3.0},
> {'Width': 2.0, 'Depth': 6.0, 'Name': 'Int_Circ_01',
> 'Parent': 'Circulation_01', 'Height': 3.0},
> {'Width': 2.0, 'Depth': 5.0, 'Name': 'Int_Circ_02',
> 'Parent': 'Circulation_01', 'Height': 3.0},
> {'Width': 2.0, 'Depth': 6.5, 'Name': 'Int_Circ_03',
> 'Parent': 'Circulation_02', 'Height': 3.0},
> {'Width': 2.0, 'Depth': 5.0, 'Name': 'Int_Circ_04',
> 'Parent': 'Circulation_02', 'Height': 3.0},
> {'Width': 2.0, 'Depth': 5.0, 'Name': 'Int_Circ_05',
> 'Parent': 'Circulation_03', 'Height': 3.0},
> {'Width': 2.0, 'Depth': 5.0, 'Name': 'Int_Circ_06',
> 'Parent': 'Circulation_03', 'Height': 3.0},
> ]
>
> so a for loop is used to iterate the list, like:
>
> for element in elements:
> create object with the desired width, depth, name, etc
>
> The thing is that there can only be a "Circulation" by story, so I am
> thinking in adding each created object to a built_Objects list and
> appending the created object to the list, like:
>
> for element in elements:
> create element
> append element['Name'] to built_Objects
>
> My question is, how can I check how many times "Circulation" appears in
> the built_Objects list? I think that if I get the number of times /N/
> that "Circulation" appears I can multiply the next circulation elevation
> /N/ times and avoid having two circulations in the same level. Is this a
> correct reasoning?
>
> I did a little research and found that count could help me, so I tried:
>
> print Built_Elements.count('Circulation')
>
> but well is not working. The result is 0, I guess that count is looking
> for the exact term and not something similar
>
> If you know the solution or a better way to do this please let me know.
Yes, count() is looking for exact matches. You can make a new list with
just the circulation names and take the length of that; something like this:
len([name for name in built_Objects if name.startswith('Circulation')])
or perhaps slightly more efficient (Python 2.5):
sum(1 for name in built_Objects if name.startswith('Circulation'))
Kent
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