johnf wrote:
> Hi,
> I want to find a item within a large tuple that contains tuples.
> mytuple = (('name',123,'value'),('first',345,'newvalue'))
> so a 'for loop' works
> istrue = False
> for i in range(len(mytuple)):
> if 'first' in mytuple[i]:
This is better written as iteration over mytuple directly, there is no
need for the index:
for t in mytuple:
if 'first' in t:
> istrue = True
> break
> if istrue:
> print " true"
>
> Is possible to use a generator or list comp. All I want to know is it True
> or
> False that mytuple contains 'first'.
Use any() in Python 2.5:
In [1]: mytuple = (('name',123,'value'),('first',345,'newvalue'))
In [2]: help(any)
Help on built-in function any in module __builtin__:
any(...)
any(iterable) -> bool
Return True if bool(x) is True for any x in the iterable.
In [5]: any('first' in x for x in mytuple)
Out[5]: True
In [6]: mytuple = (('name',123,'value'),('last',345,'newvalue'))
In [7]: any('first' in x for x in mytuple)
Out[7]: False
Kent
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