As far as I can tell:
because (c in "crab") membership is in parentheses it is more binding than
the [==] comparison. That is why it returns true/false first.
I incorrectly wrote before:
" The [in] operator takes precedence"
http://docs.python.org/ref/summary.html
-Isaac
On 3/14/07, Isaac <[EMAIL PROTECTED]> wrote:
a, b, c, or d is a type('str') not boolean which is what (c in "crab") is.
The [in] operator takes presedence, the first 3 times (c in "crab") returns
true and the last returns false; but the strings a, b, c, or d do not ==
true or false - therefore the test (c == (c in "crab")) always returns
false.
(I think)
cheers
-Isaac
reference:
http://docs.python.org/ref/summary.html
Terry wrote:
>>> for c in "abcd":
... print (c == c in "crab"), (c == (c in "crab"))
...
True False
True False
True False
False False
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