Here is a test sample of what I have: This currently correctly
identifies the start and the end of the changelog entries and I can
identify the requested item records. What I am struggling with at
present is to how to create records of the full changelog entries for
each of the found items.
Again any help greatly appreciated.
uid = "000028.txt"
file = open("C:\projects\SuiteSpecification\Notes\ChangeLog.txt")
output = file.readlines()
changeLogList = []
itemList = []
for strOut in output:
if "----" in strOut:
changeLogStart = 1
itemList.append(strOut)
if "Reviewed:" in strOut:
changeLogStart=0
for item in itemList:
if uid in item:
print item
Dean Gardner
Test Engineer
Barco
Bonnington Bond, 2 Anderson Place, Edinburgh EH6 5NP, UK
Tel + 44 (0) 131 472 5731 Fax + 44 (0) 131 472 4799
www.barco.com
[EMAIL PROTECTED]
-----Original Message-----
From: Kent Johnson [mailto:[EMAIL PROTECTED]
Sent: 03 May 2007 13:46
To: Gardner, Dean
Cc: [email protected]
Subject: Re: [Tutor] Text matching
Gardner, Dean wrote:
> Hi Folks
>
> I wish to isolate certain changelog entries and display them to the
> user, for example:
>
> Changelog.txt
>
> ----------Some Module <Tag> ---------- M 000751 - Title
>> what was amended
> Reviewed by: Someone
>
> For this text file I wish to find all entries for 000751 and then
> present each of the changelog entries.
>
> My thought was to
> identify the "----" with a regular expression identifying this as the
> changelog start
You probably don't need a regex here, something like
if line.startswith('----------'):
will probably work
> attempt to find the item number
if line.split()[1] == '000751':
> if it isn't found move on, if it is found then add this to a list.
>
> But I feel as though there must be a simpler and more effecient way.
This sounds good to me except for the regex. Can you show us your code?
Kent
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