Sorry, I don't think Hotmail has turn off HTML. If it does I havn't been able
to find it. I think you're going to have to explain your little bit of text
stuff down there at the bottom. I have no idea what most of that means. All
my choice things are working now though. I think that is what you were trying
to help me with. What I used wasif shape in["1","circle"]:and if shape == "1"
or shape =="circle":It works perfectly fine now.Ya that little bit o' code is
really puzzling. I wish I knew more about this python deal. I understand the
concept, but not the rules or the techniques and things of that sort. OK...
I've got it... the data=raw_input('Feed Me!'). Ok I now understand that bit.
Then it says Feed Me! and you put 42 (the ultimate answer to life the
universe, everything). OK, it won't accept the <type 'str'> bit. it doesn't
like the "<". Well, I just removed that bit and it said:Feed Me! and I put
42, and it said >>> (I guess it's satisfied now, with the whole feeding). Well
if I understood what 'str' meant, then I could probably figure the rest out.
Well I have to go do other things so I'll save the rest of this figuring out
till later.I shall return,Adam> Date: Wed, 23 May 2007 12:12:16 -0400> From:
[EMAIL PROTECTED]> To: [EMAIL PROTECTED]> CC: [email protected]> Subject: Re:
[Tutor] trouble with "if"> > adam urbas said unto the world upon 05/23/2007
11:57 AM:> > > > Hi all,> > > > I've been working with this new program that I
wrote. I started out > > with it on a Ti-83, which is much easier to program
than python. Now > > I'm trying to transfer the program to python but its
proving to be quite > > difficult. I'm not sure what the whole indentation
thing is for. And > > now I'm having trouble with the if statement things. > >
> > #"Circle Data Calculation Program:"> > print "Welcome to the Circle Data
Calcuation Program."> > print> > > > #"Menu 1:"> > print "Pick a shape:"> >
print "(NOTE: You must select the number of the shape and not the shape > >
itself)"> > print "1 Circle"> > print "2 Square"> > print "3 Triangle"> > > >
#"User's Choice:"> > shape=raw_input("> ")> > > > #"Select Given:"> >
if shape == 1:> > print "Choose the given value:"> > print "1
radius"> > print "2 diameter"> > print "3 circumference"> >
print "4 area"> > > > #"User's Choice:"> > given=raw_input("> ")> > > > if
given == 1:> > radius=raw_input("Enter Radius:")> >
diameter=(radius*2)> > circumference=(diameter*3.14)> >
area=(radius**2*3.14)> > print "Diameter:", diameter> > print
"Circumference:", circumference> > print "Area:", area> > > > if given
== 2:> > diameter=raw_input("Enter Diameter:")> >
radius=(diameter/2)> > circumference=(diameter*3.14)> >
area=(radius**2*3.14)> > print "Radius:", radius> > print
"Circumference:", circumference> > print "Area:", area> > > > if given
== 3:> > circumference=raw_input("Enter Circumference:")> >
radius=(circumference/3.14/2)> > diameter=(radius*2)> >
area=(radius**2*3.14)> > print "Radius:", radius> > print
"Diameter:", diameter> > print "Area:", area> > > > if given == 4:> >
area=raw_input("Enter Area:")> > radius=(area/3.14)> > >
> This is the whole program so far, because I haven't quite finished it > >
yet. But I tried to get it to display another list of options after you > >
select a shape but it just does this.> > > > Pick a shape:> > 1 Circle> > 2
Square> > 3 Triangle> > >1> > >1> > >>>> > > > I'm not sure why it does that
but I do know that it is skipping the > > second list of options.> > > >
Another of my problems is that I can't figure out how to get it to > > accept
two different inputs for a selection. Like I want it to accept > > both the
number 1 and circle as circle then list the options for > > circle. It won't
even accept words. I can only get it to accept > > numbers. It's quite
frustrating actually.> > > > Any advice would be greatly appreciated.> > Thanks
in advance,> > Adam> > > > > > > Adam,> > Could you send plain text email
rather than html, please? At least for > me, your code's indentation is all
messed up unless I take some steps > to rectify it.> > The problem is that
raw_input returns a string, and you are testing > whether given is equal to
integers. See if this helps make things clear:> > >>> data = raw_input('Feed
me!')> Feed me!42> >>> type(data)> <type 'str'>> >>> data == 42> False> >>>
int(data) == 42> True> >>>> > Best,> > Brian vdB
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