Luke, Albert:
Thanks.. yes I'm thinking re is what I need... and using negative values for
west, and positive for east is our convention. The problem I have is that
not all the data was provided in that format, so I'm in the process of
converting...
There are a number of problems with my original post. For one, the
conversion to decimal fails if given a negative number (i.e. -9 30' in my
approach becomes 8.5 when it should be 9.5). So, to get around that I need
to use abs, and add some if cases to convert it back to negative..
Anyway, still working through this...
On 7/11/07, Albert Weiss <[EMAIL PROTECTED]> wrote:
John: One way to handle the situation of longitude is to make everything
west of the Greenwich meridan a negative value until -180 degrees and
everything east of Greenwich a positive value. HTH.
Albert
*John <[EMAIL PROTECTED]>*
Sent by: [EMAIL PROTECTED]
07/10/2007 04:22 PM
To
[email protected] cc
Subject
[Tutor] An interesting case... of east vs. west
I was trying to read in a tab delimited file i was given with lat and lon,
the thing is I needed decimal lat, and decimal long... well, anyway I think
you can see what my problem was:
for i in range(0,344)
y=d[i][2].split('\xb0')
x=d[i][3].split('\xb0')
ydeg,ymin=y[0].strip(),y[1].rstrip('\' N').rstrip("\' S")
xdeg,xmin=x[0].strip(),x[1].rstrip("\' E").rstrip("\' W")
if re.search('\ZW','x[1]') xmin=-1*xmin
if re.search('\ZS','y[1]') ymin=-1*ymin
declat=int(ydeg)+(float(ymin)/60)
declon=int(xdeg)+(float(xmin)/60)
The thing is, it isn't terribly robust (I'm not even positive it's working
correctly!!). For instance, as you might have guessed I was given Lat and
Lon in the following format:
STNA 45° 49' N 08° 38' E
STNB 46° 58' 19° 33' E
STNC 53°33' -9°54'
STND 51°32' N 12°54' W
Some indicating north or some, and some not. This wasn't a concern, as I
knew they were all North. However, the West / East issue is another story.
Anyone have a more elegant solution?
-john
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