Andy Cheesman wrote:
> Dear nice people
>
> I'm trying to match a row (b) within a large numpy array (a). My most
> successful attempt is below
>
> hit = equal(b, a)
> total_hits = add.reduce(hit, 1)
> max_hit = argmax(total_hits, 0)
> answer = a[max_hit]
>
> where ...
> a = array([[ 0, 1, 2, 3],
> [ 4, 5, 6, 7],
> [ 8, 9, 10, 11],
> [12, 13, 14, 15]])
>
> b = array([8, 9, 10, 11])
>
>
>
> I was wondering if people could suggest a possible more efficient route
> as there seems to be numerous steps.
As an APL programmer I appreciate your approach.
I'm not a numpy expert. I'm assuming one can apply *for* to an array to
iterate thru the rows. Try this:
for ix, row in enumerate(a):
if row == b:
break
else:
ix = 0
Cheers,
nice person
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