At 10:28 AM 8/14/2007, you wrote:
>Dick Moores wrote:
> > At 06:47 AM 8/14/2007, Kent Johnson wrote:
> >> This could be a list comprehension:
> >> d = [ [k, 0] for k in range(200) ]
> >
> > So you recommend using list comprehensions wherever possible? (I sure
> > wouldn't have thought of that one..)
>
>Not "whenever possible", no, but I find simple list comps (I count this
>one as simple) to be far more readable than the equivalent loop. Not
>only are they shorter but they read the way I think.
>
>If the list comp can't be easily written on one line, or has a complex
>condition, or has two for clauses, I find it less appealing and may
>write it as a for loop. I never use a list comp just for the
>side-effects; only when I actually want the list.
Got it.
> > I prefer the index (or integer) to come after the bar ends, and before
> > the count. One reason is that if the index is at the base of the bar, at
> > 100 and above, the bars get pushed out one character longer than they
> > should be relative to the 99 or less bars. I suppose there's a way to
> > handle this, but I couldn't think of it then (but see below).
>
>Use string formatting or str.rjust():
>In [1]: '%3d' % 10
>Out[1]: ' 10'
>In [2]: '%3d' % 100
>Out[2]: '100'
>In [4]: str(10).rjust(3)
>Out[4]: ' 10'
So:
for i, count in enumerate(d):
barLength = count//barLengthAdjuster
print "%3d %s %d" % (i, '*' * barLength, count)
Or:
for i, count in enumerate(d):
barLength = count//barLengthAdjuster
print str(i).rjust(3), '*' * barLength, count
Right? (Anyway, they work!)
Terrific! Two ways!
> > This would solve the problem I mentioned above caused by putting the
> > indices at the bases of the bars:
> >
> > for i, count in enumerate(d):
> > barLength = count//barLengthAdjuster
> > if i < 100:
> > print "%d %s %d" % (i, '*' * barLength, count) # there are 2
> > spaces between %d and %s
> > else:
> > print "%d %s %d" % (i, '*' * barLength, count)
>
>Ouch. See above.
Ouch? No like? (I know, your 2 ways are both easier.)
Thanks much again, Kent.
Dick
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