yes, but I mean if I have the line like this: line = """38166 us::Video_Cat::Other; us::Video_Cat::Today Show; us::VC_Supplier::bc; 1002::ms://bc.wd.net/a275/video/tdy_is.asf; 1003::ms://bc.wd.net/a275/video/tdy_is_.fl;"""
I want to get the part "us::MSNVideo_Cat::Other; us::MSNVideo_Cat::Today Show; us::VC_Supplier::Msnbc;" but re.compile(r"(us::.*) .*(1002|1003).*$") will get the "1002::ms://bc.wd.net/a275/video/tdy_is.asf;" included in an lazy mode. How can i filter it out in the re? Thanks, Daniel On 9/16/07, Tom Tucker <[EMAIL PROTECTED]> wrote: > > Yep, looks like it. > > >>> line = 'us::blah blah2 1002 blah3' > >>> import re > >>> TAG_pattern = re.compile(r"(us::.*) .*(1002|1003).*$") > >>> if TAG_pattern.search(line): > ... print 'we have a match' > ... > we have a match > >>> > > >>> line2 ='us::blah blah2 1001 blah3' > >>> if TAG_pattern.search(line2): > ... print 'we have a match' > ... else: > ... print 'no match found' > ... > no match found > > > > On 9/16/07, 王超 <[EMAIL PROTECTED]> wrote: > > hi, > > > > I want to match the regular expression from right to left, such as: > > > > TAG_pattern = re.compile(r"(us::.*) .*(1002|1003).*$") > > TAG_pattern.search(line) > > > > Does the search method support this? > > > > Thanks, > > Daniel > > > > _______________________________________________ > > Tutor maillist - Tutor@python.org > > http://mail.python.org/mailman/listinfo/tutor > > > > >
_______________________________________________ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
