Ian Witham wrote: > As Michael points out, you need to explicitly use the round function, as > the float formatting merely truncates anything after the second decimal > place.
No. I don't know what algorithm it uses for rounding, but it does round: In [3]: '%.2f' % 6.6666 Out[3]: '6.67' In [4]: '%.2f' % 6.665 Out[4]: '6.67' In [5]: '%.2f' % 6.664 Out[5]: '6.66' The round() function seems to be aware of limits of representation and takes them into account. 10.825 is not exactly represented in floating point: In [8]: 10.825 Out[8]: 10.824999999999999 String formatting is literal in its rounding; 10.824999999999999 is closer to 10.82 than 10.83: In [15]: '%.2f' % 10.825 Out[15]: '10.82' round() seems to know about this: In [12]: round(10.825, 2) Out[12]: 10.83 This is not surprising after what is above, but perhaps a bit disturbing: In [13]: round(10.824999999999999, 2) Out[13]: 10.83 Kent _______________________________________________ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
