"linda.s" <[EMAIL PROTECTED]> wrote
>I have a string a= "qq,eee,rrr".
>>>> a.index(",")
> 2
> It is the position of the first "," in a.
> Is that possible to find the Nth "," in a if a is a very long string
> and I need know the position of the Nth ","?
Yes but not directly.
index takes a couple of optional parameters
S.index(sub [,start [,end]]) -> int
So by repeating the index call in a loop using the previous
index as youur start position you an get it
untested pseudo code
def nth_index(aString, aChar, N):
n = 0
for i in range(N):
n = aString.index(aChar, n)
return n
This should return the Nth index value or raise a
ValueError if less than N occurences exist
HTH,
--
Alan Gauld
Author of the Learn to Program web site
http://www.freenetpages.co.uk/hp/alan.gauld
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