Decorate level2 with a decorator that caches:
http://aspn.activestate.com/ASPN/Cookbook/Python/Recipe/425445
--Michael
On 11/1/07, Kent Johnson <[EMAIL PROTECTED]> wrote:
>
> I am building a list like this:
>
> tree = []
> for top in tops:
> l2 = level2(top)
> if l2:
> tree.append((top, l2))
>
> I would really like to turn this into a list comprehension:
>
> tree = [ (top, level2(top)) for top in tops if level2(top) ]
>
> but the call to level2() is expensive enough that I don't want to repeat
> it. Is there any way to do this or am I stuck with the (IMO ugly) loop
> form?
>
> Kent
>
> who actually does have a question occasionally :-)
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--
Michael Langford
Phone: 404-386-0495
Consulting: http://www.TierOneDesign.com/
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