I would always use the os functions to find the basename, but
You could exploit the fact that Windows considers the extension to be
whatever is after the last "." character.
fn = fn[:fn.rfind(".")]
>> > What I found is this:
>> > import os
>> > myfile_name_with_path = 'path/to/my/testfile.txt'
>> > basename = os.path.basename(myfile_with_path)
>> > filename = os.path.splitext(basename)
>> > myfile_name_without_suffix = filename[0]
>>
>> The last two can be easily combined as:
>>
>> > myfile_name_without_suffix = os.path.splitext(basename)[0]
>>
>> But otherwise you are using the "correct" mechanism if
>> you want a reliable result.
> Thanks for this confirmation.
>
> I am happy to have made some tiny progress in my python learings...
>
> Kind regards,
> Timmie
>
> _______________________________________________
> Tutor maillist - [email protected]
> http://mail.python.org/mailman/listinfo/tutor
>
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