"bhaaluu" <[EMAIL PROTECTED]> wrote In addition to Kents comments about dictionaruy access I think there may be another problem in your logic.
> The first loop is supposed to populate G with > a random range of 4 integers 10 to 109 > in random keys 1-19 that have a zero (except keY 6 and keY 11) > So keY 6 and keY 11 should both have a zero in G after the > four integers have been sown. > > if keY == 6 or keY == 11 or tablE.values()[keY-1][6] != 0: > tablE.values()[5][6] = 0 > tablE.values()[10][6] = 0 > cnt -= 1 > keY = random.choice(a) This detects any of the exception cases so a simple else clause should be sufficient for the others. However if you really want an explicit check... > if keY != 6 or keY != 11 or table.values()[keY-1][6] == 0: This test should use 'and' rather than 'or' since you want all of the conditions to be true, not just one of them. But since the failing condituions should all have been caught above simply using else here would do what I think you want. > b = range(10,110) # 10 to 109 > integer = random.choice(b) > tablE.values()[keY-1][6] = integer > cnt += 1 -- Alan Gauld Author of the Learn to Program web site http://www.freenetpages.co.uk/hp/alan.gauld _______________________________________________ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor