> -----Original Message----- > From: [EMAIL PROTECTED] > [mailto:[EMAIL PROTECTED] On Behalf Of Dick Moores > Sent: Thursday, April 17, 2008 2:21 PM > To: Python Tutor List > Subject: Re: [Tutor] datetime module problem > > At 06:29 AM 4/17/2008, Kent Johnson wrote: > >Dick Moores wrote: > > > >>>You could either create n with hours=minutes=0, or round the > >>>difference up to the next whole number of days. > >>I have no idea how to implement either of your suggestions as to > >>how to eliminate it. Could you please spell them both out? > > > >1. > > > >In [17]: n=datetime.today() > >In [18]: n=datetime(n.year, n.month, n.day) > >In [19]: n > >Out[19]: datetime.datetime(2008, 4, 17, 0, 0) > > > >2. > > > >In [20]: diff=y-n > >In [21]: diff > >Out[21]: datetime.timedelta(0, 57464, 721369) > >In [22]: days = diff.days > >In [23]: if diff.seconds or diff.microseconds: > > ....: days += 1 > > ....: > > ....: > >In [24]: days > >Out[24]: 1 > > Thanks, Kent. So here's where I am now: > <http://py77.python.pastebin.com/f5da44111> > > The script calculates correctly, but note the output, lines 34, 39, > 49, 53. Please show me how to print these in the form 4/17/2007. I've > tried everything I could think of. > > Dick >
In [23]: import datetime In [24]: x = datetime.datetime.now() In [25]: x Out[25]: datetime.datetime(2008, 4, 17, 14, 24, 18, 447000) In [26]: x.month Out[26]: 4 In [27]: x.day Out[27]: 17 In [28]: x.year Out[28]: 2008 In [30]: print "%s/%s/%s" %(x.month, x.day, x.year, ) 4/17/2008 Does that help? There's probably another way to do it, but this seems to work. Mike _______________________________________________ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
